Respuesta :

Answer:

the ones that you would drag on the 35x-20 should be 5(7x-4)  and 5(-4+7x).

For the 40x+16 should be 4(10x+4) and 2(8+20x) and for the neither one it should be 2(10x+8) so hopefully that is the correct answer for all of them

Step-by-step explanation:

xKavinsky

Answer:

4(10x+4)   ⇒ 40x + 16

2(8+20x) ⇒ 40x + 16  

5(7x-4)   ⇒ 35x - 20  

5(-4+7x) ⇒ 35x - 20  

2(10x+8) ⇒ 20x + 16     Neither

Step-by-step explanation:

Given Expression:

4(10x+4)

2(8+20x)

5(7x-4)

5(-4+7x)

2(10x+8)

Solve:

4(10x+4)   ⇒ 40x + 16                      {4 · 10x = 40}     {4 · 4 = 16}

2(8+20x) ⇒ 40x + 16                       {2 · 8 = 16 }        {20 · 2 = 40x}

5(7x-4)   ⇒ 35x - 20                       { 5 · 7x = 35x}      {5 · - 4 = -20}

5(-4+7x) ⇒ 35x - 20                       { 5 · -4 = -20 }       {5 · 7x = 35x}

2(10x+8) ⇒ 20x + 16                        {2 · 10x = 20x}      { 2 · 8 = 16}

Hence,

4(10x+4)   ⇒ 40x + 16

2(8+20x) ⇒ 40x + 16  

5(7x-4)   ⇒ 35x - 20  

5(-4+7x) ⇒ 35x - 20  

2(10x+8) ⇒ 20x + 16  Neither

Kavinsky  

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