The required moles of water and anhydrous salt in the given reaction is 0.06 moles.
What is the relation between mass & moles?
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
- W = given mass
- M = molar mass
From the given data, mass of left water will be calculated by substracting the mass of CuSO₄ from the anhydrous salt as:
- Mass of Left water = 1.6 - 0.5 = 1.1 g
- Moles of left water = 1.1g / 18g/mol = 0.06 moles
Chemical reaction will be represented as:
CuSO₄.XH₂O → CuSO₄ + XH₂O
From the stoichiometry of the reaction it is clear that 0.06 moles of water is produced from 0.06 moles of anhydrous compound.
Ratio of the moles of water to salt = 0.06 / 0.06 = 1
So name of the compound CuSO₄.H₂O is copper sulfate monohydrate.
Hence, 0.06 moles of water as well as anhydrous compound is involved in the reaction and name of the obtained compound is copper sulfate monohydrate.
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