A body moves in an x-y plane with velocity vm/s. The components of v are vx = 5m/s and vy = 7m/s along x and y-axes respectively. What is the magnitude and direction of the velocity?​

Respuesta :

The magnitude and direction of the velocity will be 8.60 m/sec and 54.4°.

What is velocity?

The change of displacement with respect to time is defined as the velocity.  velocity is a vector quantity. it is a time-based component.

Velocity at any angle is resolved to get its component of x and y-direction.

Given data;

[tex]\rm v_x= 5 \ m/sec \\\\ v_y=7 \ m/sec[/tex]

The magnitude of the resultant velocity is;

[tex]\rm v_{net}=\sqrt{v_x^2+v_y^2}\\\\ \rm v_{net}=\sqrt{5 ^2+7^2 } \\\\ v_{net}=\sqrt{74} \\\\ v_{net}= 8.60 \ m/sec[/tex]

The direction of the velocity is;

[tex]\rm tan \theta = \frac{v_y}{v_x} \\\\ \theta = tan^{-1}(\frac{7}{5}) \\\\ \theta =54.4^0[/tex]

Hence the magnitude and direction of the velocity will be 8.60 m/sec and 54.4°.

To learn more about the velocity refer to the link ;

https://brainly.com/question/862972

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