The integral that is needed to solve the demand function is R(x) = 599x - 0.14[tex]x^{3/2}[/tex]
A demand function describes the mathematical relationship between the quantity demanded and one or more determinants of the demand, as the price of the good or service, the price of complementary and substitute goods, disposable income, etc.
Here, given differential equation;
R'(x) = 599 - 0.21[tex]\sqrt{x}[/tex]
we can also write this as;
[tex]\frac{d}{dx}R(x) = 599 - 0.21\sqrt{x}[/tex]
[tex]d R(x) = (599 - 0.21\sqrt{x} ) dx[/tex]
On integrating both sides, we get
[tex]\int\ d R(x) = \int\ (599 - 0.21\sqrt{x} ) dx[/tex]
R(x) = [tex]599x - 0.21 X \frac{2}{3}x^{3/2}[/tex] + C
R(x) = 599x - 0.14[tex]x^{3/2}[/tex] + C ...........(i)
Also given, at x = 0, R(x) = 0, Put these values in equation (i), we get
0 = 0 - 0 + C
C = 0
Put the value of C in equation (i), we get
R(x) = 599x - 0.14[tex]x^{3/2}[/tex]
Thus, the integral that is needed to solve the demand function is R(x) = 599x - 0.14[tex]x^{3/2}[/tex]
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