A proton with kinetic energy 82.6 eV is seen to move in a circular path while in a region with a uniform magnetic field. What kinetic energy must an electron have if it is to move in a circular path of the same size

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11-07-2022
Physics

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A proton with kinetic energy 82.6 eV is seen to move in a circular path while in a region with a uniform magnetic field. What kinetic energy must an electron have if it is to move in a circular path of the same size

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anshumanaryan799 anshumanaryan799 · Answer 1 · 2022-07-19T19:34:47+02:00

The electron must have 2.065 MeV of energy if it is to move in a circular path of the same size.

For a particle of mass m and charge Q in a magnetic field, the radius of the path is given by,

r = [tex]\sqrt{2m}(KE)/qB[/tex]

q ∝[tex]\sqrt{m (KE)}[/tex]

e/2e =[tex]\sqrt{(mp)(IMeV)}/(4mp)(KE)[/tex]

1/4 = 8.26/(4)(KE)

KE = 2.065 MeV

Kinetic energy is a type of energy that an object or particle has due to its motion. When work is done on an object by applying a net force that transfers energy, the object accelerates, thereby gaining kinetic energy.

Learn more about Kinetic Energy here: https://brainly.com/question/25959744

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