The magnitude of a vertical electric field that will balance the weight of a plastic sphere of mass 2. 1 g that has been charged to -3. 0 NC is 6.86 × [tex]10^{6}[/tex] N/C.
An electric field is the physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field of a system of charged particles.
It is given that,
Mass of sphere, m = 2.1 g =0.0021kg
Charge,q = ₋3nC = ₋ 3 ₓ [tex]10^{-9}[/tex]
To balance the weight of a plastic sphere, we must determine the magnitude of the electric field. So,
[tex]ma= qE[/tex]
a = g
[tex]E = \frac{mg}{q}[/tex]
E = [tex]\frac{0.0021 * 9.8}{-3 * 10^{-9} }[/tex]
E = 6860000 N/C
E = 6.86 × [tex]10^{6}[/tex] N/C
Hence, the magnitude of the electric field that balances its weight is 6.86 × [tex]10^{6}[/tex] N/C .
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