By using collinearity assumptions and addition and subtraction of line segments, the length of the line segment AB is 26 units.
Let A, B, D, F be points lying on the same line such that A(x) ≤ B(x) ≤ D(x) ≤ F(x), where x is the position of each point on a number line. Then, the value of the length of the line segment AB is:
AB = AD + DF - BF
AB = 26 + 8 - 8
AB = 26
Please notice that B(x) = D(x) as AB = AD.
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