The length of a rectangle is 4 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle.
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The dimensions are 3 inches, 10 inches, and 13 inches.
It should be noted that the diagonal is the longest side. This will be solved by using Pythagoras theorem.
Therefore,
(2x + 6)²
4x²+ 24x + 36
Reduce to lowest term
x² + 6x + 9
x² + 3x + 3x + 9
x(x + 3) - 3(x + 3)
(x - 3) = 0
x = 0 + 3 = 3
Therefore x = 3
Therefore the dimensions will be:
x = 3
2x + 4 = 2(3) + 4 = 10
2x + 6 = 2(3) + 6 = 12
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