olution:
iven;
[tex]\log_52x=3[/tex][tex]\log_52x=3[/tex]
Applyin the power property of logarithm given as;
[tex]\log_ba=c\Leftrightarrow a=b^c[/tex]
Thus;
[tex]\operatorname{\log}_52x=3\Leftrightarrow2x=5^3[/tex]
Simplify further, we have;
[tex]\begin{gathered} 2x=5\times5\operatorname{\times}5 \\ \\ 2x=125 \end{gathered}[/tex]
ivide both sides by 2;
[tex]\begin{gathered} \frac{2x}{2}=\frac{125}{2} \\ \\ x=\frac{125}{2} \end{gathered}[/tex]
NSWER:
[tex]x=\frac{125}{2}[/tex]
