Respuesta :
The pressure in a 17.0-L cylinder filled with 46.5 g of oxygen gas at a temperature of 320 K is 2.26 atm.
IDEAL GAS LAW:
The pressure of a given gas can be calculated by using the ideal gas law equation as follows:
PV = nRT
Where,
P = Pressure
V = Volume
n = Number of moles
R = Gas law constant (0.0821 molK/Latm)
T = Temperature
Given,
V = 17 L
T = 320 K
R (Gas constant) = 0.0821
According to this question, a 17.0- l cylinder filled with 46.5 g of oxygen gas at a temperature of 320 K.
The number of moles of the oxygen gas (O₂) = 46.9g ÷ 32g/mol = 1.46mol
∴ PV = nRT
P × 17 = 1.46 × 0.0821 × 320
⇒17P = 38.357
⇒P = 38.357 ÷ 17
⇒P = 2.26 atm
Therefore, the pressure in a 17.0-L cylinder filled with 46.5 g of oxygen gas at a temperature of 320 K is 2.26 atm.
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