kayleebeaton
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Find an equation for the nth term of the sequence. -4, -16, -64, -256, ...

a. an = 4 • -4n
b. an = 4 • -4n + 1
c. an = -4 • 4n
d. an = -4 • 4n - 1

Respuesta :

apologiabiology
ok, so seems to be geometric
an=a1(r)^(n-1)

a1=first term
r=commonr atio
n=number of term
first term is -4
common ratio is -16/-4=4

so
a1=-4
r=4

[tex]a_n=-4(4)^{n-1}[/tex]

D is the answer
shubhamchouhanvrVT

The nth term of the sequence is [tex]a_n= -4(4)^{n-1}[/tex]. Option D is correct.

What is geometric progression?

When there is a constant between the two successive numbers in the series then it is called a geometric series.

The formula for finding the nth term is,

[tex]a_n = a(r)^{n-1}[/tex]

Given series is -4, -16, -64, -256, ...

a₁ = -4 and r = -16 / -4 = 4

The nth term will be calculated as:-

[tex]a_n = -4(4)^{n-1}[/tex]

Therefore, the nth term of the sequence is [tex]a_n= -4(4)^{n-1}[/tex]. Option D is correct.

To know more about geometric progression follow

https://brainly.com/question/12006112

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