Respuesta :
His mistake is that he didn't need to remove one even number on the spinner, so we just need to take 2/5×1/5=2/25.
Answer and Explanation:
Given : A spinner with equal sections numbered from 1 to 5 is spun twice. Raul is finding the probability that both spins will result in an even number.
He did [tex]\frac{2}{5}\times \frac{1}{4}=\frac{2}{20}[/tex]
To find : His mistake and correct it ?
Solution :
Outcomes = {1,2,3,4,5}
Total outcomes = 5
Even number = {2,4}
Favorable outcome of getting even number = 2
Probability of getting an even number is [tex]\frac{2}{5}[/tex]
When he spin twice there is no change in probability.
So, The probability that both spins will result in an even number is
[tex]P=\frac{2}{5}\times \frac{2}{5}[/tex]
[tex]P=\frac{4}{25}[/tex]
The mistake in Rahul's calculation is he apply replacement which is not applied in this.
