Answer: Area of the base of the pyramid [tex]=294\sqrt{3}\text{ cm}^2[/tex]
Step-by-step explanation:
Since we have given that
The base of a regular pyramid is a hexagon.
so, hexagon must be regular too.
We need to find the area of the base of the pyramid i.e. area of hexagon.
As we know that there are 6 equilateral triangles in a hexagon.
And length of each side = 14 cm
As we know the formula for "Area of equilateral triangle":
[tex]Area=\frac{\sqrt{3}}{4}\times a^2[/tex]
so, Area of base of the pyramid is given by
[tex]6\times \frac{\sqrt{3}}{4}\tiems a^2\\\\=6\times \frac{\sqrt{3}}{4}\times 14\times 14\\\\=294\sqrt{3}\text{ cm}^2[/tex]
