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Norma kicks a soccer ball with an initial velocity of 10.0 meters per second at an angle of 30.0°. If the ball moves through the air for 3.2 seconds, what is the horizontal distance traveled by the ball? Round your answer to the nearest tenth.

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Answer

27.7


Explanation

The ball was hit at an angle of 30°, with the horizontal at a speed of 10 m/s. We have to find the horizontal component of speed.

cosx = adjacent/hypotenuse

cos 30 = adjacent / 10

adjacent = 10 cos30

             = 8.66 m/s        ⇒ This is the horizontal speed.

Now  find the horizontal distance.

Distance = speed × time

               = 8.66 × 3.2

                = 27.71

Answer to the nearest tenth = 27.7

Answer:

27.7 m

Explanation:

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