the x int (where the line crosses the x axis) is (-2,0)
the y int (where the line crosses the y axis) is (0,-2)
(-2,0)(0,-2)
slope = (-2 - 0) / (0 - (-2) = -2/2 = -1
y = mx + b
slope(m) = -1
use either of ur points (-2,0)...x = -2 and y = 0
sub and find b
0 = -1(-2) + b
0 = 2 + b
-2 = b
so ur equation in slope intercept form is : y = -x - 2
y = -x - 2
x + y = -2
x + y + 2 = 0 <== general form
there can be 2 answer for point slope form...
y - y1 = m(x - x1)
slope(m) = -1
(-2,0)...x1 = -2 and y1 = 0
sub
y - 0 = - (x - (-2)
y - 0 = -(x + 2) <=== point slope form
y - y1 = m(x - x1)
slope(m) = -1
(0,-2)...x1 = 0 and y1 = -2
sub
y - (-2) = - (x - 0)
y + 2 = - (x - 0) <== point slope form