Respuesta :
The correct answer is:
0.3439.
Explanation:
This is a binomial probability. This is because there are two outcomes; either a digit is 0 or it is not. Since the digits are used with replacement, the probability of one digit being a 0 does not affect the probability of a second digit being 0. Finally, there are a fixed number of trials; we are choosing 4 digits.
Since we want the probability that at least one digit is a zero, we want the complement of "no digits are zero". This means we will find P(X = 0) and subtract it from 1.
The formula for a binomial distribution with n trials and r successes is
[tex] P(X=r)=_nC_r(p)^r(1-p)^{n-r} [/tex]
In this situation, n is 4, since we are choosing 4 digits. r is 0, since we are finding the probability that no digits are 0. p is 0.1, since there is a 1/10 chance of a digit being 0. This gives us:
[tex] P(X=0)=_4C_0(0.1)^0(1-0.1)^l{4-0}
\\
\\=\frac{4!}{0!4!}(0.1)^0(0.9)^4
\\
\\=1(1)(0.9^4)=0.6561 [/tex]
This means that the complement of P(X=0), or the probability that at least one digit is 0, is 1-0.6561 = 0.3439.