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Mrs. Meyers is growing vines along the sides of her house. On the west side the vines are 2 4/10 meters tall. On the east side the vines are 5 8/10 meters taller than the ones on the west side. How tall are the vines on the east side?

Respuesta :

e=east vine’s height

e=24/10+58/10
e=82/10

e=8 1/5

Height of the vines on the west side

[tex] =2\frac{4}{10} [/tex]

But

[tex] =\frac{4}{10}=\frac{2}{5} [/tex]

So length of vines in the west

= [tex] =2\frac{2}{5} [/tex]

Height of vines on the west side as an improper fraction

= [tex] \frac{12}{5} [/tex]

Now Vines on the east are

[tex] 5\frac{8}{10}=5\frac{4}{5} [/tex]

taller

In the mixed fraction it is

[tex] \frac{29}{5} [/tex]

So height of vines

[tex] =\frac{29}{5}+\frac{12}{5} [/tex]

[tex] =\frac{41}{5} [/tex]

[tex] =8\frac{1}{5} [/tex]

So the vines on the east are [tex] 8\frac{1}{5} m [/tex]

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