PLEASE ANSWER QUICKLY! : There are four questions here please make sure to click through, I got the first answer from someone but they neglected to go through the photos. Oh well xD Any help is appreciated
2 ) We know the perimeter of the regular hexagon to be 12 cm and the apothem to be [tex] \sqrt{3} [/tex] cm
The area formula of a regular hexagon is: Area = [tex] \frac{1}{2} [/tex] × perimeter × apothem
Let us substitute: A = [tex]( \frac{1}{2})(12)( \sqrt{3} ) [/tex] = [tex] 6\sqrt{3} [/tex] cm² Your answer will be the second option
3 ) We know the value of the apothem to be 16.9 cm and the side length to be 14 cm
The perimeter of this octagon is: P = 8 x side = 8 x 14 = 112 cm
Area formula of a regular octagon is A = [tex] \frac{1}{2} [/tex] perimeter x apothem A = [tex] \frac{1}{2} [/tex] ( 112 )( 16.9 ) = 946 .4 cm² Your answer will be the last option
4 ) The apothem of the regular pentagon is given to be 5.5 cm and the side is 8 cm
The perimeter of this pentagon is: P = 5 x side = 5 x 8 = 40 cm
Area formula of a pentagon is: Area = [tex] \frac{1}{2} [/tex] x apothem x perimeter = [tex] \frac{1}{2} [/tex] ( 5.5 ) ( 40 ) = 110 cm² Your answer will be the third option
5 ) The apothem of this hexagon is[tex] 9\sqrt{3} [/tex] cm and the side is 18 cm
The perimeter of the hexagon is P = 6 x side = 6 x 18 = 108 cm
The area formula of a regular hexagon is Area = [tex] \frac{1}{2} [/tex] x apothem x perimeter = [tex] \frac{1}{2} [/tex] ( 108 )( [tex] 9\sqrt{3} [/tex] ) = 841 cm² Your answer will be the first option
