Respuesta :

It would be
[tex] \sqrt{8} [/tex]
Or
[tex] 2\sqrt{2} [/tex]

Answer:

The equation of circle of radius r whose centre is the origin (0, 0) ,

It is given by:    [tex]x^2+y^2 =r^2[/tex]                    ......[1]

Given the equation: [tex]x^2+y^2 =8[/tex]

To find the radius of the circle;

Compare the given equation with [1] we have;

[tex]r^2 = 8[/tex]

Taking square root both sides we get;

[tex]r = \sqrt{8} = 2\sqrt{2}[/tex] units

Therefore, the radius of the circle is, [tex]2\sqrt{2}[/tex] units