Answer:
Impulse, J = 4.14 kg-m/s
Explanation:
It is given that,
Mass of the ball, m = 0.06 kg
Initial speed of the ball, u = -28 m/s (it is assumed that the initial direction of the ball is in the -x direction)
Final speed of the ball, v = 41 m/s
It can be assumed to find the impulse delivered to the ball by the racket. The impulse delivered is equal to the change in momentum of the object. Mathematically, it is given by :
[tex]J=m(v-u)[/tex]
[tex]J=0.06\times (41-(-28))[/tex]
J = 4.14 kg-m/s
So, the impulse delivered by the ball to the racket is 4.14 kg-m/s. Hence, this is the required solution.
