A computer randomly puts a point inside the rectangle. What is the
probability that the point does not land in triangle T?

A computer randomly puts a point inside the rectangle What is the probability that the point does not land in triangle T class=

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Answer:

Option B. 5/6

Step-by-step explanation:

we know that

The probability that the point does not land in triangle T is equal to subtract the area of triangle T from the area of rectangle and divided the result by the  the area of rectangle

so

Find out the area of rectangle

[tex]A=(6)(4)=24\ unit^2[/tex]

Find out the area of triangle T

[tex]A=\frac{1}{2}(2)(4)=4\ unit^2[/tex]

The probability is equal to

[tex]P=\frac{24-4}{24}=\frac{20}{24}=\frac{5}{6}[/tex]

Answer:

3/8

Step-by-step explanation: