Step-by-step explanation:
When we observe the figure there are two semicircles , one of radius 14cm . And other will be of 14cm/2 = 7cm ( Since the 2nd semi circle is drawn taking radius of 1st semicircle as diameter.)
Now join T to the center of 2nd semi circle . Therefore , we have
[tex]\tt\to PR = 28cm \\\\\tt\to PQ + 14cm = 28cm \\\\\tt\to PM + MQ = 14cm \\\\\tt\to MQ = 14cm - 7cm \\\\\to\boxed{\orange{\tt MQ = 7cm }}[/tex]
Now , looking at the figure we know that radius is perpendicular to the tangent at point of contact . Here TR is tangent . Therefore ∆TRM is right angled triangle. Using Pythagoras Theorem we have,
[tex]\tt\to 21^2 = RT^2+7^2 \\\\\tt\to RT^2= 441 - 49 \\\\\tt\to RT =\sqrt{392}\\\\\tt\to\boxed{\orange{\tt RT = 19 .79 cm }}[/tex]
