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4. Mario was asked to find the GCF of 15, 30, and 45. What number did he find? A. 15 C. 45 B. 30 D. 60

5. 60 notebooks, 48 ball pens, and 36 correction tapes are shared among a number of grade 5 pupils so that each gets an equal number of each kind. How many of each kind can each pupil get? A. 4 C. 12 B. 8 D. 16

6. What are the first 4 multiples of 4? A. 2, 4, 8, and 12 C. 4, 8, 16, 20 B. 4, 8, 12, 16 D. 4, 8, 16, 24

please answer it correctly ​

Respuesta :

reinhard10158

Step-by-step explanation:

4.

GCF : greatest common factor, the biggest number all these numbers can be divided by without remainder.

so, 15, 30 and 45

let's find the basic factors of each

15/2 no

15/3 = 5

5/3 no

5/4 no

5/5 = 1

therefore, 3¹×5¹

30/2 = 15

15/3 = 5

5/3 no

5/4 no

5/5 = 1

therefore, 2¹×3¹×5¹

45/2 no

45/3 = 15

15/3 = 5

5/3 no

5/4 no

5/5 = 1

therefore, 3²×5¹

the largest combination of factors they all have is 3¹×5¹ = 15

so, the GCF = 15.

5.

since I don't know how many pupils there are this is a strange question.

or does this text mean there are 5 pupils ?

overall, there is something wrong with this question.

so, let's answer based on some assumptions :

the GCF (as in 4.) is 12

12×3 = 36

12×4 = 48

12×5 = 60

so, if there are 12 students, each one gets 5 notebooks, 4 ball pens and 3 correction tapes.

if there are 5 students, then each one gets 60/5 = 12 notebooks, 48/5 = 9 (3 remainder) ball pens and 36/5 = 7 (1 remainder) correction tapes.

6.

multiples of 4, that means 4*x with x = 1, 2, 3, 4, ...

so

4×1 = 4

4×2 = 8

4×3 = 12

4×4 = 16

therefore, B is the right answer.

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