A cylinder was found in a storeroom of a manufacturing plant. The label on the cylinder was gone, and
no one remembered what the cylinder held. A 0.00500-gram sample was found to occupy 4.13 mL at 23°C
and 745 torr. The sample was also found to be composed of only carbon and hydrogen. Identify the gas

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pstnonsonjoku pstnonsonjoku · Answer 1 · 2021-10-13T11:54:15+02:00

The gas that is to be identified in the problem is C2H2

From the ideal gas equation;

PV = nRT

P = pressure of the gas = 745 torr or 0.98 atm

V = volume of the gas = 4.13 mL or 0.00413 L

n = number of moles of the gas = ?

R = gas constant = 0.082 atm Lmol-1K-1

T = temperature of the gas = 23°C + 273 = 296 K

n = PV/RT

n = 0.98 atm × 0.00413 L/0.082 atm Lmol-1K-1 × 296 K

n = 0.00405/24.272

n = 0.000167 moles

Recall that;

Number of moles = mass/molar mass

molar mass = mass/Number of moles

molar mass = 0.00500-gram/0.000167 moles

molar mass = 30 g/mol

Since it is a hydrocarbon;

[12 +1]n = 30

n = 30/13

n = 2

The gas is C2H2

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